What would be the time period of a pendulum when taken to the moon?

What would be the time period of a pendulum when taken to the moon?

Solution(By Examveda Team) When the pendulum is taken to the moon, the value of ‘g’ will decrease and hence time period will increase. As the pendulum takes more time to complete one vibration, it will lose time.

What will be the time period of simple pendulum when taken on moon if its time period on earth is 2s?

Therefore, the time period of a second’s pendulum on the surface of the moon will be $2\sqrt 6 s$.

How much will be the length of a simple pendulum if its time period is one second?

Answer: A simple pendulum with a period of 1 second will have a length of 0.25 meters or 25 centimeters.

What is the ratio between the period of a pendulum on the moon and the period of an identical pendulum on earth?

If you know that that free fall acceleration g on the Moon is about 6 times less than on the Earth, it gives you the answer: on the Moon the same pendulum will have a period about √6≈2.45 longer than on the Earth.

How does the time period of simple pendulum vary with its length?

The longer the length of string, the farther the pendulum falls; and therefore, the longer the period, or back and forth swing of the pendulum. The greater the amplitude, or angle, the farther the pendulum falls; and therefore, the longer the period.)

What is the length and time period of seconds pendulum?

A seconds pendulum is a pendulum whose period is precisely two seconds; one second for a swing in one direction and one second for the return swing, a frequency of 0.5 Hz.

Does time period of simple pendulum depends on length?

Answer: (a) The period of a simple pendulum equals 2 times π times the square root of the length of the pendulum over g, the acceleration due to gravity. 2, π, and g are constant, so the only variable is L. Therefore the period is dependent on the length.

Why is a pendulum called a seconds pendulum?

That is why we call it a seconds pendulum. So, in this formula, T is time period, l is the effective length of a pendulum and g is the acceleration due to gravity. On the surface of the earth, the effective length of a pendulum should be 99.2 cm so that its time period becomes 2 seconds and hence, we call it a seconds pendulum.

What is the law of length of simple pendulum?

Law of Length: The time period of the simple pendulum is directly proportional to the square root of its length. This property is known as the law of length. Law of Iscochronism: The time period of the simple pendulum is independent of the amplitude, provided the amplitude is sufficiently small.

What is the effective length of a pendulum on the Moon?

On the surface of the earth, the effective length of a pendulum should be 99.2 cm so that its time period becomes 2 seconds and hence, we call it a seconds pendulum. When we go the moon, the acceleration due to gravity decreases.

What is the frequency of oscillation of a simple pendulum?

The Frequency of Oscillation of a Simple Pendulum: The period of a simple pendulum is given by Where l = Length of a simple pendulum, g = acceleration due to gravity Now the frequency is related to period as n = 1 /T